AP EAPCET 06-Jul-2022 Shift 1 Paper

Given Equation for trajectory of a projectile,
y=(‌

x

√3

−‌

x2

60

)m .......(i)
To find velocity of projection of projectile comparing with equation
y=x‌tan‌θ−‌

g

2µ2cos2θ

⋅x2......(ii)
We get, tan‌θ=‌

1

√3

∴θ‌=30∘
cos‌30∘‌=‌

√3

2

......(iii)
Also, ‌

g

2µ2cos2θ

=‌

1

60

g=10m∕ s2,cos2θ=cos230∘=(‌

√3

2

)2=‌

3

4

‌

10

2u2×cos230∘

=‌

1

60

⇒u2=‌

10×60

2×‌ 3 4

⇒u2=‌

1200

3

=400
⇒u=√400⇒u=20m∕ s