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Question : 66 of 160
Marks:
+1,
-0
Solution:
Given, curve is
y3−3xy+2=0On differentiating both side w.r.t.
x, we get
‌3y2‌−3x‌−3y=0⇒‌‌‌=‌⇒‌‌‌=‌‌ or ‌y−‌ The tangen in vertical when
‌=0y−‌‌=0y2‌=x⇒‌‌y2=x ⇒(0,0),(1,1) and
(1,−1) are the three points but
(0,0) and
(1,−1) does not satisfy
y3−3xy+2=0.
∴‌‌V={1,1}
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