AP EAPCET 06-Jul-2022 Shift 1 Paper

Section: Mathematics

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Question : 52 of 160

Marks: +1, -0

The parabola with focus at (4,−3) and vertex at (4,−1) is

x2+8x+6y+22=0
x2−8x−10y+6=0
x2−8x−16y=0
x2−8x+8y+24=0

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