A point mass oscillates along x-axis according to x=x_{0} \sin (\omega t-\frac{\pi}{6}). If the acceleration of the point mass is written as {a}= {A} \sin (\omega {t}+\delta) then

Correct Answer is : A=x0ω2,δ=5π6

{A}= {x}_{0}, \delta=-\frac{\pi}{6}

{A}= {x}_{0} \omega^{2}, \delta=-\frac{\pi}{6}

{A}= {x}_{0} \omega^{2}, \delta=\frac{\pi}{6}

{A}= {x}_{0} \omega^{2}, \delta=\frac{5 \pi}{6}

AP EAPCET 06-Jul-2022 Shift 1 Paper

Section: Physics

Question : 100 of 160

Marks: +1, -0

A point mass oscillates along x-axis according to x=x0‌sin(ωt−‌

). If the acceleration of the point mass is written as a=A‌sin(ωt+δ) then

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