AP EAPCET 05-Jul-2022 Shift 2 Paper

Ball dropped from height h takes t second to reach on the surface of earth. Hence,
i.e
‌h=0×t+‌

1

2

gt2
‌t=√‌

2h

g

⇒‌‌t=√‌

2h

g

.......(i)
For another planet, mass Mp=100Me
where, Me is mass of the earth:
Radius of planet, Rp=10Re where, Re is the radius of earth.
The value of gravitational acceleration on the surface of planet,
gp=‌

GMp

Rp2

‌=‌

G×100Me

(10Re)2

‌=‌

GMe

Re2

=g
Since, the value of gravitational acceleration is same for other planet, hence time taken to cover same height on the planet is same as t seconds.