AP EAPCET 05-Jul-2022 Shift 2 Paper

Let the curve and the normal intersect at point (x1,y1)
x1y1=1 and ax1+by1+c=0
Differentiating xy=1 w.r.t. ' x ',
x‌

dy

dx

+y=0
⇒‌

dy

dx

|(x1,y1)=‌

−y1

x1

⇒−‌

dx

dy

|(x1,y1)=‌

x1

y1

Equation of normal is
y−y1=‌

x1

y1

(x−x1)
The product of x1y1 is positive, x1y1 are of same sign.
⇒a and b are of opposite sign.
From options, we can conclude that a>0,b<0.