Let \overline{O A}=-4 \overline{i}+3 \overline{k}, \overline{O B}=14 \overline{i}+2 \overline{j}-5 \overline{k} . \overline{O D} bisects \angle A O B and |\overline{O D}|=\sqrt{6}, then \overline{O D}=

\pm(\overline{i}+\overline{j}+2 \overline{k})

\pm( \overline{i}+2 \overline{j}+\overline{k})

\pm(2 \overline{i}+\overline{j}+\overline{k})

\pm \frac{1}\sqrt{2}(2 \overline{i}+\overline{j}+\sqrt{7} \overline{k})

AP EAPCET 05-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 33 of 160

Marks: +1, -0

Let OA=−4i+3k,OB=14i+2j−5k.OD bisects ∠AOB and |OD|=√6, then OD=

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