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Question : 29 of 160
Marks:
+1,
-0
Solution:
We have,
‌AB=‌ Position vector of ‌B−‌ Position vector of ‌A‌=−6−2+3‌|AB|=√36+4+9=7‌BC=‌ Position vector of ‌C−‌ Position vector of ‌B‌=−2+3−6 ‌|BC|=√4+9+36=7‌CD=6+2+‌|CD|=√36+4+1=√41‌DA=2−3+2 ‌|DA|=√4+9+4=√17‌AC‌=−8+−3‌=AB+BC∴ABCD is a quadrilateral which is not a parallelogram.
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