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Question : 21 of 160
Marks:
+1,
-0
Solution:
We have,
‌‌=‌‌‌=90−‌ ‌⇒tan(‌+‌)=tan(90−‌)‌⇒‌‌‌| tan‌+tan‌ |
| 1−tan‌‌tan‌ |
=cot‌‌⇒‌‌‌| tan‌+tan‌ |
| 1−tan‌‌tan‌ |
=‌‌⇒‌‌tan‌‌tan‌+tan‌‌tan‌‌=1−tan‌‌tan‌
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