AP EAPCET 05-Jul-2022 Shift 1 Paper

Given, rA‌=10‌cm=0.1m
rB‌=100m
rC‌=5‌cm=0.05m
weight placed on piston A=m×g
=2g
Using Pascal's law;
‌

FA

AA

‌=‌

FB

AB

=‌

FC

AC

⇒‌‌‌

2g

π(01)2

‌=‌

FB

π(100)2

=‌

FC

π(0.05)2

.....(i)
From Eq. (i) we have
FB‌=‌

2g

π(0.1)2

×‌

π(100)2

1

=‌

2×10000×g

0.01

‌=2×106g
Similarly, FC‌=‌

π(0.05)2

1

×‌

2g

π(0.1)2

‌=‌

0.0025

0.01

×2g=0.50g
Hence, B can lift mass of 2×106‌kg and C can lift mass of 0.50‌kg.
Therefore, no option is correct.