AP EAPCET 05-Jul-2022 Shift 1 Paper

The given situation is shown belowLet v be the velocity of solid cylinder on reaching the ground.
According to conservation of energy,
Total energy at point A= Total energy at point B
‌‌ i. e ‌mgh+0=‌

1

2

Iω2+‌

1

2

mv2+0
‌⇒‌‌mgh=‌

1

2

(‌

1

2

MR2)(‌

v

R

)2+‌

1

2

mv2
‌⇒(‌ Where, ‌I=‌

1

2

MR2‌ and ‌ω=‌

v

R

)
‌⇒‌‌gh=‌

v2

4

+‌

v2

2

⇒gh=‌

3v2

4

‌⇒‌‌v2=‌

4gh

3

⇒v=√‌

4gh

3