© examsiri.com
Question : 70 of 160
Marks:
+1,
-0
Solution:
∫dx=logf(x)+C I=∫ Since,
x3−2x−4=(x−2)(x2+2x+2) On putting
x=2,A=1 and comparing coefficients of
x2, we get
0=A+B⇒B=−1On putting
x=0, we have
2A−2C So,
f(x)=f(3)=f(3)==
© examsiri.com
Go to Question: