AP EAPCET 05-Jul-2022 Shift 1 Paper

Slope of line joining the points (0,3) and (5,−2) is ‌

3+2

0−5

=−1
This is equal to the slope of tangent on the curve and that is given by
‌‌

dy

dx

=‌

−c

(x+1)2

⇒‌

dy

dx

=−1
⇒c=(x+1)2......(i)
Equation of line joining the points (0,3) and (5,2) is given by (y−3)=−1(x−0).
Solving equation of tangent and the curve for point of intersection
‌

c

x+1

+x=3......(ii)
Solving Eqs. (i) and (ii),
x=1
On putting this in Eq. (ii), we get c=4