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Question : 45 of 160
Marks:
+1,
-0
Solution:
Given, lines
‌y−m1x=0.....(i)
‌y−m2x=0.....(ii)
‌⇒(y−m1x)(y−m2x)=0‌y2−(m1+m2)xy+m1m2x2=0Now,
ax2+2hxy+by2=0‌∴‌‌2=‌⇒a=2b‌⇒‌‌‌=‌
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