Considering the question to be, to find the roots of the equation x4−2x3+x−380=0 Now, by trial error method we find that x=5 is a solution to the equation ⇒‌‌54−2×53+5−380=0 ‌=625−250+5−380=0 ‌=380−380=0 Thus, x=5 is a solution. We also find that x=−4 is a solution ‌(−4)4−2×(−4)3−4−380=0 ‌=256+128−4−380 ‌=380−380=0 The real roots are 5 and −4. Sum of real roots are 5+(−4)=1