AP EAPCET 05-Jul-2022 Shift 1 Paper

When two short magnets of equal dipole moments M are fastened perpendicularly at their centres. Then their resultant dipole moment is given asM′‌=√M12+M22+2M1M2‌cos‌θ
‌=√M2+M2+2MM‌cos‌90∘
⇒M′‌=M√2....(i)
The magnitude of the magnetic field at a distance d from the centre on the bisector i.e at a distance d on the axial position of dipole,
B‌=‌

µ0

4π

⋅‌

2M′

d3

‌=‌

µ0

4π

⋅‌

2√2M

d3

[from Eq. (i)]