AP EAPCET 04-Jul-2022 Shift 2 Paper

(c) Since, uniform solid sphere of radius R produces a gravitational acceleration a0 on its surface, hence
a0=‌

Gm

R2

where, m is the mass of solid sphere.
Let x be the distance of the point from the surface of sphere where the gravitational acceleration becomes ‌

a0

4

.
i. e.
‌

a0

4

=‌

a0

(1+‌ x R )2

⇒(‌

1

2

)2=‌

1

(1+‌ x R )2

⇒‌

1

2

=‌

1

1+‌ x R

⇒1+‌

x

R

=2
⇒x=R
Hence, distance of the point from the centre of sphere =x+R=R+R=2R