AP EAPCET 04-Jul-2022 Shift 2 Paper

Mass of ball, m=300g=0.3‌kg height, h=10m.
If v be the speed of ball when it reaches the ground, then
‌v2=u2+2gh=0+.2×10×10
‌⇒‌‌v=200⇒v=10√2m∕ s
‌
For sandy ground, initial velocity of ball,
v=10√2m∕ s
Final velocity v′=0
distance travelled by the ball in sand, s=1.5m if a′ be retardation applied on the ball in sandy ground, then using equation
v′2=v2−2as
0=(10√2)2−2a×1.5⇒a=‌

200

3

m∕ s2
∵ Average resistance offered by the sand
F=m⋅a=0.3×‌

200

3

=20N