AP EAPCET 04-Jul-2022 Shift 2 Paper

The given situation is shown below
At time t=0 object is at point A with a distance of 3‌cm.
At time t=2 s object reaches from point A to point B. i.e in negative direction of X-axis.
∴ Distance travelled by the object in 2 s,
d‌=3−(−5)=3+5=8‌cm
d‌=8

∧

i

Initial velocity of object along X-axis,
v=−12

∧

i

‌cm∕ s
By using second equation of motion,
d=ut+‌

1

2

at2
⇒8

∧

i

=−12

∧

i

×2−‌

1

2

a×4⇒8

∧

i

=−24

∧

i

−2a
⇒2a=−32

∧

i

⇒a=−16

∧

i

‌cm∕ s2