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Question : 76 of 160
Marks:
+1,
-0
Solution:
(a)
(|cos‌t|sin‌t+|sin‌t∣cos‌t)‌dt ‌=|cos‌t|sin‌t+|sin‌t|cos‌t‌dt =‌‌sin‌2t‌dt−‌‌sin‌2t‌dt+‌‌sin‌2t‌dt−‌‌sin‌2t⋅dt ‌‌=‌[‌]π∕4π∕2−‌[‌]π∕25π∕4+‌[‌]π∕4π−[‌]π5π∕4 =‌(cos‌π−‌)+‌(cos‌−cos‌π)‌(cos‌2‌π−‌)+‌(cos‌−cos‌2‌π)‌=‌(−1−0)+‌(0−(−1))−‌(1−0)+‌(0−1)‌=‌+‌−‌−‌=0
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