© examsiri.com
Question : 67 of 160
Marks:
+1,
-0
Solution:
(d) Given,
y2=4ax and
xy=i2 cut orthogonally.
Let they intersect at
(x1,y1).
∴‌‌y2=4ax⇒2y‌=4a ⇒‌=‌∴‌‌(x1,y1)=‌........(i) and
‌‌xy=c2‌⇒‌‌y+x‌=0‌⇒‌‌‌(x1,y1)=−‌......(ii) From Eqs (i) and (ii), we get
‌‌‌×−‌=−1 ⇒‌‌x1=2a From
y2=4ax ‌⇒‌‌y1=√4a⋅2a=2√2a⇒x1y1=c2‌⇒‌‌2a(2√2a)=c2⇒‌=4√2‌⇒‌‌c4=32a4‌
© examsiri.com
Go to Question: