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Question : 53 of 160
Marks:
+1,
-0
Solution:
Given, equation of ellipse
‌+‌=1Thus,
a2=4,b2=9Since,
b>a.
So, the major axis of ellipse is
Y-axis
‌e2=1−‌=1−‌=‌‌e=‌ Thus, foci of ellipse be
(0,±be)=(0,±√5) So,
S=(0,√9) and
s′=(0,−√5)Given, point on ellipse is
p(‌,‌).
Thus, focal distance
PS‌=√(‌−0)2+(‌−√5)2=√‌+‌‌=√‌=√4=2 ‌ and focal distance ‌PS′‌=√(‌−0)2+(‌+√5)2‌=√‌=√‌‌=√16=4 Thus, required focal distances are 4,2 .
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