AP EAPCET 04-Jul-2022 Shift 2 Paper

The given equation of circles
‌S1:x2+y2+8x+2y+10=0
‌S2:x2+y2+7x+3y+10=0
As we know the equation of radical axis of two circles is given by
S1‌−S2=0
⇒(x2+y2+8x+2y+10)
‌−(x2+y2+7x+3y+10)=0
⇒(8x−7x)+(2y−3y)=0
⇒x−y=0
Thus, equation of radical axis of the given circle is x−y=0
Hence, the image of the point (3,4) with respect to y=x line is (4,3).