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Question : 133 of 160
Marks:
+1,
-0
Solution:
(c) Lime water is
Ca(OH)2. Acidity of lime water is 2 .
So, Normality
= Acidity
× Molarity
⇒‌ Molarity ‌=‌MConcentration of
[OH−]ions,
[OH−]=2×‌=0.01M ‌ Now, ‌pOH‌=−log[OH−]pOH‌=−log‌10−2⇒‌‌pOH‌=2‌log‌10=2pH+pOH‌=14⇒‌‌pH‌=14−pOH=14−2Thus,
pH=12
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