A hydrometer executes simple harmonic motion when it is pushed down vertically in a liquid of density \rho. If the mass of hydrometer is m and the radius of the hydrometer tube is {r}, then the time period of oscillation is

Correct Answer is : T=2π√mπr2ρg

T=2 \pi \sqrt{\frac{m}{\pi r^{2} \rho g}}

{T}=2 \pi \sqrt{ {\pi^{2} \rho g}/{ {m}}}

{T}=\frac{1}{2 \pi} \sqrt{ { {m}/{\pi {r}^{2} \rho {g}}}

{T}=\frac{1}{2 \pi} \sqrt{ {\pi {r}^{2} \rho {g}}/{ {m}}}

AP EAPCET 04-Jul-2022 Shift 1 Paper

Section: Physics

Question : 91 of 160

Marks: +1, -0

A hydrometer executes simple harmonic motion when it is pushed down vertically in a liquid of density ρ. If the mass of hydrometer is m and the radius of the hydrometer tube is r, then the time period of oscillation is

T=2π√‌
m
πr2ρg
T=2π√‌
π2ρg
m
T=‌
1
2π
√‌
m
πr2ρg
T=‌
1
2π
√‌
πr2ρg
m

Validate

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