AP EAPCET 04-Jul-2022 Shift 1 Paper

The given situation is shown belowLet a be the common acceleration in the system of combination of blocks, then equation of motion of block m1 is
T=m1a
T=40a....(i)
and equation of motion of block m2 is
F−T‌=m2a
⇒1000−T‌=m2a
⇒1000−T‌=60×(‌

T

40

)
[from Eq. (i)]
‌⇒1000−T=‌

3

2

T⇒2000−2T=3T
‌⇒‌‌T=‌

2000

5

=400N