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Question : 55 of 160
Marks:
+1,
-0
Solution:
Equation of hyperbola
‌−‌=1......(i)
Let
(h,k) be the point whose chord of contact subtends a right angle at the centre of hyperbola. Equation of chord of contact
‌−‌=1 Squaring both the sides, we get
‌(‌)2+(‌)2−2‌⋅‌=(1)2⇒‌‌‌+‌−‌⋅xy=1.....(ii)
Now, from Eqs. (i) and (ii), we have
The above equation represents a pair of perpendicular lines if
coefficient of
x2+ coefficient of
y2=0 ‌‌−‌+‌+‌=0⇒‌‌‌+‌=‌−‌ Replacing
h→x and
k→y,
‌+‌=‌−‌
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