Let \overline{a}=x \overline{i}+y \overline{j}+z \overline{k} and x=2 y. If |\overline{a}|=5 \sqrt{2} and \overline{a} makes and angle of 135^{\circ} with the {z}-axis then \overline{a}=

Correct Answer is : 2√5i+√5j−5k

2 \sqrt{3 i}+\sqrt{3} \overline{j}-3 \overline{k}

2 \sqrt{6} i+\sqrt{6} \overline{j}-6 \overline{k}

2 \sqrt{5} \overline{i}+\sqrt{5} \overline{j}-5 \overline{k}

2 \sqrt{5} i+\sqrt{5} j+5 \overline{k}

AP EAPCET 04-Jul-2022 Shift 1 Paper

Section: Mathematics

Question : 32 of 160

Marks: +1, -0

Let a=xi+yj+zk and x=2y. If |a|=5√2 and a makes and angle of 135∘ with the z-axis then a=

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