AP EAPCET 04-Jul-2022 Shift 1 Paper

Section: Mathematics
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Question : 3 of 160
 
Marks: +1, -0
For i=1,2,3 and j=1,2,3 If ai2+bi2+ci2=1,aiaj+bibj+cicj=0,‌‌∀i≠j and A=[
a1a2a3
b1b2b3
c1c2c3
]
then det(AAT)=
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