AP EAPCET 04-Jul-2022 Shift 1 Paper

From the given situation absolute refractive index of denser medium, ‌aµd=2
Absolute refractive index of rarer medium, ar=1
∴ Refractive index of denser medium with respect to rarer medium
‌rµd=‌

‌aµd

aaµr

=‌

2

1

=2⇒‌rµd=2
If ic be the critical angle, then
sin‌ic‌=‌

1

rµd

=‌

1

2

=sin‌30∘
⇒‌‌ic‌=30∘