AP EAMCET Medical 24 Apr 2019 Shift 2 Paper
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Question : 115 of 160
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The horizontal and vertical components of the electric field of an electromagnetic wave in free space are respectively
E x = 2 sin (ωt + βz)
E y = 2 cos (ωt + βz)
Then the displacement current density is (Take j =√ − 1 )
Then the displacement current density is (Take j =
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