AP EAMCET Medical 2018 Shift 2 Paper
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Question : 93 of 160
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The rubber cord of a catapult has a cross-sectional area 1 m m 2 and unstretched length 10 cm. If it is stretched to a length 12 cm and a body of mass 5 g is projected from it. then the velocity of projection of the body is
(Young’s modulus of rubber = 5 ×10 8 N m − 2 )
(Young’s modulus of rubber = 5 ×
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