A particle moves along a circular path of radius R such that its speed 'v' depends upondistance V as per the relation v = α \sqrts where 'α' is a positive constant. Acceleration of the particle after traversing a distance 's' is

Correct Answer is : α2√14+s2R2

AP EAMCET Medical 2018 Shift 2 Paper

Question : 84 of 160

Marks: +1, -0

A particle moves along a circular path of radius R such that its speed 'v' depends upondistance V as per the relation v = α √s where 'α' is a positive constant. Acceleration of the particle after traversing a distance 's' is

α2√
1
4
−
s2
R2
α2√
1
4
+
s2
R2
α2√
1
2
+
s2
R2
α2√
1
2
−
s2
R2

Validate

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