AP EAMCET Medical 2015 Paper
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Question : 97 of 160
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An object is thrown towards the tower which is at a horizontal distance of 50 m with an initial velocity of 10 m s − 1 and making an angle 30° with the horizontal. The object hits the tower at certain height. The height from the bottom of the tower where the object hits the tower is (g = 10 m s − 2 )
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