A simple pendulum with a bob of mass ' m ' density \sigma and length l is immersed in a liquid of density \rho. If it make small oscillations, then time period of pendulum is

Correct Answer is : T=2π√1g(1−ρσ)

{\T}=2 \pi \sqrt{\frac{1}{ {\g}-\rho}}

T=2 \pi \sqrt{\frac{1}{g(1-\rho)}}

T=2 \pi \sqrt{\frac{1}{g(\rho-\sigma)}}

T=2 \pi \sqrt{ {1}/{g (1-\frac{\rho}{\sigma}) }}

AP EAMCET Medical 17 May 2024 Shift 4 Paper

Question : 91 of 160

Marks: +1, -0

A simple pendulum with a bob of mass ' m ' density σ and length l is immersed in a liquid of density
ρ. If it make small oscillations, then time period of pendulum is

T=2π√‌
1
g−ρ
T=2π√‌
1
g(1−ρ)
T=2π√‌
1
g(ρ−σ)
T=2π√‌
1
g(1−‌
ρ
σ
)

Validate

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