One mole of compound AB reacts with one mole of compound CD according to the equation {\AB}+ {\CD} ⇌ {\AD}+ {\CB} At equilibrium it was found that \frac{3}{4} mole of A B and C D had been converted to A D and C B. There is no change in volume. The equilibrium constant for the reaction is

AP EAMCET Medical 17 May 2024 Shift 2 Paper

Question : 131 of 160

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One mole of compound AB reacts with one mole of compound CD according to the equation
AB+CD⇌AD+CB
At equilibrium it was found that ‌

mole of AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

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