At 298 K , the ionization constant of {\CN}^{-}is 2.08 \times 10^{-6}. What is the ionization constant of its conjugate acid? ( {\K}_{ {\w}}=10^{-14})

Correct Answer is : 4.8×10−9

AP EAMCET Medical 17 May 2024 Shift 1 Paper

Question : 132 of 160

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At 298 K , the ionization constant of CN−is 2.08×10−6. What is the ionization constant of its conjugate acid? (Kw=10−14)

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