The electric field for an electromagnetic wave is given by E=40 \sin ( {\kZ}-6 \times 10^8 {\t}), where magnitude of {\E}_0 is in {\Vm}^{-1}. The magnitude of wave vector k is

AP EAMCET Medical 17 May 2024 Shift 1 Paper

Question : 114 of 160

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The electric field for an electromagnetic wave is given by E=40sin‌(kZ−6×108t), where magnitude of E0 is in Vm−1. The magnitude of wave vector k is

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