AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper

The equation of the projectile is given as,
y=Px−Qx2 .......(I)
The distance travelled,
y=x‌tan‌θ−

1

2

g(

x2

u2cos2θ

) .......(II)
From equation (I) and (II),
P=tan‌θ
Q=

g

2u2cos2θ

The formula for maximum height and range is,
H=

u2sin2θ

2g

R=

u2‌sin‌2‌θ

2g

By dividing the two equations,

H

R

=

sin2θ

2 ×sin‌2‌θ

H

R

=

sin2θ

2×2‌sin‌θ‌cos‌θ

H

R

=

tan‌θ

4

H

R

=

P

4