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Question : 73 of 160
Marks:
+1,
-0
Solution:
Consider the integral.
I=∫dx It is solved as,
I=∫dx =‌∫xsec2 dx+∫dx =‌∫xsec2 dx+∫tan‌‌d‌x = [x−∫tan‌ ‌‌d‌x] +∫tan‌‌d‌x And,
I=x‌tan‌−∫tan‌‌d‌x+∫tan‌‌d‌x =x‌tan‌+C
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