Consider the given equation of curves. x2=3y And, x2+y2=4 Substitute 3y for x2 in the above equation. y2+3y−4=0 y(y+4)−1(y+4)=0 (y+4)(y−1)=0 y=−4,1 If y=−4, x2=−12 This is not possible. x=±√3 The point of intersection are (√3,1) and (−√3,1) So,1
dy
dx
=
2x
3
m1=
2
3
(√3) Also,1
dy
dx
=−
x
y
m2=−
x
y
=
√3
1
=√3 The angle between the curve is calculated as, tan‌θ=|