AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper

Consider the equation.
4xy+2x+6y+3=0
It can written as,
2x(2y+1)+3(2y+1)=0
(2y+1)(2x+3)=0
The equation of lines are,
x=−

3

2

And,
y=

1

2

The equation of line passing through (2,1) and perpendicularto the line x=

23

2

and y=

1

2

are,
y−1=0
x−2=0
Thus,
(x−2)(y−1)=0
xy−x−2y+2=0