AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper

The median of the given observation is calculated as,
Median =

25α+26α

2

=25.5α
The mean deviation about the median is calculated as,
Mean deviation about median =

50 ∑ k=1 |kα−25.5α|

50

50×50=

50

∑

k=1

|α(k−25.5)|
2500=|α|‌

50

∑

k=1

|α(k−25.5)|
z|α|[24.5+23.5+...+15+0.5] =2500
Solve further,
2|α|×

25

2

×(24.5+0.5)=2500
|α|×25=1400
|α|=4