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Question : 34 of 160
Marks:
+1,
-0
Solution:
It is given that the points are coplanar.
AB=−i+5j−3k BC=−3i−2j+6k CD=5i+4j+(λ−2)k So,
|AB BC CD|=0 || −1 | 5 | −3 |
| −3 | −2 | 6 |
| 5 | 4 | λ−2 |
|=0 2λ+20+15(λ−2)+150 +36−30=0 17λ+146=0 Solve further,
λ=−
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