The radius of orbit of an electron and the speed of electron in the ground state of hydrogen atom are 5.5 \times 10^{-11} m and 4 \times 10^6 ms^{-1} respectively. Then the orbital period of this electron in the first excited state will be___________

Correct Answer is : 6.908×10−16 s

AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper

Section: Physics

Question : 117 of 160

Marks: +1, -0

The radius of orbit of an electron and the speed of electron in the ground state of hydrogen atom are 5.5×10−11 m and 4×106ms−1 respectively. Then the orbital period of this electron in the first excited state will be___________

9.608×10−16 s
8.9068×10−16 s
7.806×10−16 s
6.908×10−16 s

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