AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper

The voltage across capacitance is,
Vcap=

Q

C

=

4v10−6

2×10−6

=2V
The across 2Ω resistance is same as of VCap
Therefore,
I=

V

R

I=

2

2

=1A
The formula for the emf of the cell,
E=V+Ir
Substitute the values in the above equation.
E=2+1×0.5
=2.5V