The equation of motion of a projectile is y = ax - bx^2, where a, b are constants. Match the column -1 with column - II Column - I Column - II i) The initial velocity of projection a/b ii) The horizontal range of projectile a\sqrt{2/{bg} iii) The maximum height attained by projectile \frac{a^2}{4b} iv) The time of flight of projectile \sqrt{\frac{g(1+a^2)}{2b}} i ii iii iv 1 2 3 4 a d d a b a a d c b c c d c b b

AP EAMCET Engineering 25 Apr 2017 Shift 1 Paper

Section: Physics

Question : 84 of 160

Marks: +1, -0

The equation of motion of a projectile is y=ax−bx2, where a, b are constants. Match the column -1 with column - II

Column - I

Column - II

The initial velocity of projection

ii)

The horizontal range of projectile

a√

iii)

The maximum height attained by projectile

iv)

The time of flight of projectile

√

g(1+a2)

	i	ii	iii	iv
1 2 3 4	a d d a	b a a d	c b c c	d c b b

Go to Question:

Prev Question

Next Question