If a^{-} and b^{-} are not perpendicular to each other, r^{-}\timesa^{-}=b^{-}\timesa^{-} and r^{-}.c^{-}=0 then r^{-}=

Correct Answer is : −b−(−b.−c−a.−c)−a

b^{-}-({b^{-}.c^{-}}/{a^{-}.c^{-}})a^{-}

b^{-}+({b^{-}.c^{-}}/{a^{-}.c^{-}})a^{-}

AP EAMCET Engineering 25 Apr 2017 Shift 1 Paper

Section: Mathematics

Question : 31 of 160

Marks: +1, -0

−

and

−

are not perpendicular to each other,

−

and

−

=0 then

−

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