AP EAMCET Engineering 25 Apr 2017 Shift 1 Paper

Section: Mathematics
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Question : 1 of 160
 
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Let N be the set of all natural numbers and f:N→N be such that 1990 < f(1990) < 2100 and satisfies the equation
x−f(x)=19[
x
19
]
−90[
f(x)
90
]
,

where [y] denotes the greatest integer less than or equal to y. Then the number of possible value of f(1990) is
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