(\frac{1+\cos (3\theta)+i\sin (3\theta)}{1+\cos (3\theta)-i\sin (3\theta)})^{20}= ?

Correct Answer is : cos(60θ)+isin(60θ)

\cos(60\theta) + i \sin(60\theta)

\cos(60\theta) - i \sin(60\theta)

\cos (20\theta)+i\sin (20\theta)

\cos (20\theta)-i\sin (20\theta)

AP EAMCET Engineering 23 Sep 2020 Shift 1 Paper

Section: Mathematics

Question : 51 of 160

Marks: +1, -0

(

1+cos(3θ)+i‌sin(3θ)

1+cos(3θ)−i‌sin(3θ)

)20= ?

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